Mid-point of P(2,3) and Q(4,5)=(3,4) Slope of PQ=1 Slope of the line L=−1 Mid-point (3,4) lies on the line L. Equation of line L y−4=−1(x−3)⇒x+y−7=0 Let image of point R(0,0) be S(x1,y1) Mid-point of RS=(
x1
2
,
y1
2
) Mid-point (
x1
2
,
y1
2
) lies on the line (i) ∴x1+y1=14 Slope of RS=
y1
x1
Since RS⟂ line L ∴
y1
x1
×(−1)=−1 ∴x1=y1 From (ii) and (iii), x1=y1=7 Hence the image of R=(7,7)