AB=√(1+2)2+(9−3)2=√45 BC=√(3−1)2+(8−9)2=√5 AC=√(3+2)2+(8−3)2=√50 ∴(√50)2=(√45)2+(√5)2 (AC)2=(AB)2+(BC)2 ∠B=90∘ ⇒ABC is right angled triangle. Circumcentre = Mid-point of hypotenuse = Mid-point of AC =(
1
2
,
11
2
) Mid-point of line BC=(2,
17
2
) Line passing through circumcentre and bisect line BC will be y−