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JEE Main Math Class 11 Trigonometric Functions Questions
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© examsnet.com
Question : 29
Total: 115
2
sin
(
π
22
)
sin
(
3
π
22
)
sin
(
5
π
22
)
sin
(
7
π
22
)
sin
(
9
π
22
)
is equal to :
[25-Jul-2022-Shift-2]
3
16
1
16
1
32
9
32
Validate
Solution:
2
sin
π
22
sin
3
π
22
sin
5
π
22
sin
7
π
22
sin
9
π
22
=
2
sin
(
11
π
−
10
π
22
)
sin
(
11
π
−
8
π
22
)
sin
(
11
π
−
6
π
22
)
sin
(
11
π
−
4
π
22
)
sin
(
11
π
−
2
π
22
)
=
2
cos
π
11
cos
2
π
11
cos
3
π
11
cos
4
π
11
cos
5
π
11
=
2
sin
32
π
11
2
5
sin
π
11
=
1
16
© examsnet.com
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