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JEE Main Math Class 11 Trigonometric Functions Questions
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© examsnet.com
Question : 34
Total: 115
The number of elements in the set
S
=
{
θ
∈
[
−
4
π
,
4
π
]
:
3
cos
2
2
θ
+
6
cos
2
θ
−
10
cos
2
θ
+
5
=
0
}
is
[29-Jun-2022-Shift-1]
Your Answer:
Validate
Solution:
3
cos
2
2
θ
+
6
cos
2
θ
−
10
cos
2
θ
+
5
=
0
3
cos
2
2
θ
+
6
cos
2
θ
−
5
(
1
+
cos
2
θ
)
+
5
=
0
3
cos
2
2
θ
+
cos
2
θ
=
0
Cos
2
θ
=
0
OR
cos
2
θ
=
−
1
∕
3
θ
∈
[
−
4
π
,
4
π
]
2
θ
=
(
2
n
+
1
)
⋅
π
2
∴
θ
=
±
π
∕
4
.
±
3
π
∕
4
.
.
.
.
.
.
.
±
15
π
∕
4
Similarly
cos
2
θ
=
−
1
∕
3
gives 16 solution
© examsnet.com
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