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JEE Main Math Class 11 Trigonometric Functions Questions
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© examsnet.com
Question : 38
Total: 115
The value of
2
sin
(
12
∘
)
−
sin
(
72
∘
)
is :
[25-Jun-2022-Shift-2]
√
5
(
1
−
√
3
)
4
1
−
√
5
8
√
3
(
1
−
√
5
)
2
√
3
(
1
−
√
5
)
4
Validate
Solution:
2
sin
12
∘
−
sin
72
∘
=
sin
12
∘
+
(
−
2
cos
42
∘
⋅
sin
30
∘
)
=
sin
12
∘
−
cos
42
∘
=
sin
12
∘
−
sin
48
∘
=
2
sin
18
∘
⋅
cos
30
∘
=
−
2
(
√
5
−
1
4
)
⋅
√
3
2
=
√
3
(
1
−
√
5
)
4
© examsnet.com
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