⋅(3x−2)=21 ‌‌mC1,‌mC2,‌mC3‌ are in A.P. ‌ ‌‌ 2. ‌‌mC2=‌mC1+‌mC3 Solving for m, we get m=2‌ (rejected), ‌7 Put in equation (1) ‌21.(10−3x)‌
3x
9
=21 ‌3x=30,32 ‌x=0,2 Sum of the squares of all possible values of x=4