The given line is polar or P(2,β) w.r.t. given circle x2+y2−4x−6y−3=0 Chord or contact ‌αx+βy−2(x+α)−3(y+β)−3=0 ‌⇒(α−2)x+(β−3)y−(2α+3β+3)=0 . . . (i) ∵ But the equation of chord of contact is given as : x+y−3=0 . . . (ii) comparing the coefficients ‌
α−2
1
=‌
β−3
1
=−(‌
2α+3β+3
−3
) On solving α=−6 β=−5 Now ‌‌4α−7β=11