=2+3i ‌z2+3i=(z−2+i)(2+3i) ‌z2+3i=2z−4+2i+3iz−6i−3 ‌z2+3i=(2z−7)+i(3z−4) ‌z2−(2+3i)z+(7+7i)=0 This is a quadratic in z. ‌z1+z2=2+3i ‌z1+z2=7+7i ‌z12+z22=(z1+z2)2−2z1z2 ‌=(2+3i)2−2(7+7i) ‌=4−9+12i−14−14i ‌=−19−2i