x = 9 Directrix of an ellipse Ee=31, Directrix x=31⇒a=3Now b2=a2(1−e2)=9(1−91)=8∴ Eq. of ellipse = 9x2+8y2=1focus (±ae,0)=(±1,0)Locus of mid point of chord T = S,T⇒9xh+8yk−1=0S⇒9h2+8k2−1=0AB passes through (1, 0)∴9h=9h2+8k2or 9k2=8h(1−h)9y2=8x(1−x)