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JEE Main Math Class 12 Application of Derivatives Part 2 Questions

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Question : 42

Total: 100

Let f and g be twice differentiable even functions on (−2,2) such that f(‌

)=0, f(1)=1 and g(‌

)=0,g(1)=2. Then, the minimum number of solutions of f(x)g′′(x)+f′(x)g′(x)=0 in (−2,2) is equal to____

[29-Jun-2022-Shift-2]

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