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JEE Main Math Class 12 Application of Integrals Questions
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© examsnet.com
Question : 1
Total: 78
The area, enclosed by the curves
y
=
sin
x
+
cos
x
and
y
=
|
cos
x
−
sin
x
|
and the lines
x
=
0
,
x
=
π
2
, is
[1 Sep 2021 Shift 2]
2
√
2
(
√
2
−
1
)
2
(
√
2
+
1
)
4
(
√
2
−
1
)
2
√
2
(
√
2
+
1
)
Validate
Solution:
Area
=
∫
0
π
2
(
(
cos
x
+
sin
x
)
−
|
cos
x
−
sin
x
|
)
d
x
=
∫
0
π
4
(
(
cos
x
+
sin
x
)
−
(
cos
x
−
sin
x
)
)
d
x
+
∫
π
4
π
2
(
(
cos
x
+
sin
x
)
−
(
sin
x
−
cos
x
)
)
d
x
=
2
∫
0
π
4
sin
x
d
x
+
2
∫
π
4
π
2
cos
x
d
x
=
2
(
−
1
√
2
+
1
)
+
2
(
1
−
1
√
2
)
=
2
√
2
(
√
2
−
1
)
© examsnet.com
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