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JEE Main Math Class 12 Application of Integrals Questions
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© examsnet.com
Question : 62
Total: 78
The area of the region bounded by the curve
y
=
x
3
,
and the lines,
y
=
8
,
and
x
=
0
,
is
[Online May 19, 2012]
8
12
10
16
Validate
Solution:
Required Area
=
8
∫
y
=
0
y
1
∕
3
d
y
=
y
1
∕
3
+
1
1
3
+
1
|
0
8
=
3
4
(
y
4
∕
3
)
|
0
8
=
3
4
[
(
8
)
4
3
−
0
]
=
3
4
[
2
4
]
=
3
4
×
16
=
12
s
q
.
unit
© examsnet.com
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