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JEE Main Math Class 12 Continuity and Differentiability Part 1 Questions
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© examsnet.com
Question : 33
Total: 100
If
x
=
√
2
cosec
−
1
t
and
y
=
√
2
sec
−
1
t
(
|
t
|
≥
1
)
,
then
d
y
d
x
is equal to.
[Online April 16, 2018]
y
x
−
y
x
−
x
y
x
y
Validate
Solution:
Here,
d
x
d
t
=
1
2
√
2
cosec
−
1
t
2
cosec
−
1
t
log
2
.
−
1
x
√
x
2
−
1
d
y
d
t
=
1
2
√
2
sec
−
1
t
2
sec
−
1
t
log
2
.
1
x
√
x
2
−
1
∴
d
y
d
x
=
d
y
d
t
d
x
d
t
=
−
√
2
cosec
−
1
t
√
2
sec
−
1
t
2
sec
−
1
t
2
cosec
−
1
t
d
y
d
x
=
d
y
d
t
d
x
d
t
=
−
√
2
sec
−
l
t
2
cosec
−
1
t
=
−
y
x
© examsnet.com
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