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JEE Main Math Class 12 Continuity and Differentiability Part 2 Questions
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© examsnet.com
Question : 2
Total: 92
If the function
f
(
x
)
=
{
72
x
−
9
x
−
8
x
+
1
√
2
−
√
1
+
cos
x
,
x
≠
0
log
e
2
log
e
3
,
x
=
0
.
is continuous at
x
=
0
, then the value of
a
2
is equal to
[4 Apr 2024 Shift 2]
968
1152
746
1250
Validate
Solution:
👈: Video Solution
lim
x
⟶
0
f
(
x
)
=
a
ln
2
ln
3
lim
n
⟶
0
72
x
−
9
x
−
8
x
+
1
√
2
−
√
1
+
cos
x
=
lim
x
⟶
0
(
8
x
−
1
)
(
9
x
−
1
)
√
2
−
√
1
+
cos
x
lim
n
⟶
0
(
8
x
−
1
x
)
(
9
x
−
1
x
)
(
x
2
1
−
cos
x
)
(
√
2
+
√
1
+
cos
x
)
∴
ln
8
×
ln
9
×
2
×
2
√
2
=
24
√
2
ln
2
ln
3
∴
a
=
24
√
2
,
a
2
=
576
×
2
=
1152
© examsnet.com
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