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Test Index
JEE Main Math Class 12 Continuity and Differentiability Part 2 Questions
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© examsnet.com
Question : 45
Total: 92
Let
f
:
[
0
,
3
]
rightarrow
R
be defined by
f
(
x
)
=
min
{
x
−
[
x
]
,
1
+
[
x
]
−
x
]
where
[
x
]
is the greatest integer less than or equal to
x
. Let
P
denote the set containing all
x
in
(
0
,
3
)
, where
f
is discontinuous and
Q
denote the set containing all
x
in
(
0
,
3
)
, where
f
is not differentiable.
Then the sum of number of elements in
P
and
Q
is equal to ............. .
[2021, 27 July Shift-1]
Your Answer:
Validate
Solution:
f
(
x
)
=
min
{
x
−
[
x
]
,
1
+
[
x
]
−
x
}
f
(
x
)
=
min
(
{
x
}
,
1
−
{
x
}
)
So, the graph of
f
(
x
)
will be
f
is continuous everywhere for
0
≤
x
≤
3
. But
f
is non-differentiable at
x
=
1
2
,
3
2
,
5
2
and
x
=
1
,
2
So, if set
A
denotes the points of discontinuity, then
n
(
A
)
=
0
.
And if set
B
denotes the points of non-differentiable, then
n
(
B
)
=
5
∴
n
(
A
)
+
n
(
B
)
=
0
+
5
=
5
© examsnet.com
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