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JEE Main Math Class 12 Continuity and Differentiability Part 2 Questions
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© examsnet.com
Question : 6
Total: 92
For
a
,
b
>
0
, let
f
(
x
)
=
{
tan
(
(
a
+
1
)
x
)
+
b
tan
x
x
x
<
0
√
a
x
+
b
2
x
2
−
√
a
x
b
√
a
x
√
x
x
>
0
.
be a continous function at
x
=
0
. Then
b
a
is equal to
[8 Apr 2024 Shift 2]
5
4
8
6
Validate
Solution:
👈: Video Solution
lim
x
⟶
0
f
(
x
)
=
f
(
0
)
=
3
lim
x
⟶
0
+
√
a
x
+
b
2
x
2
−
√
a
x
b
√
a
x
√
x
=
3
lim
x
⟶
0
+
a
x
+
b
2
x
2
−
a
x
b
√
a
x
3
∕
2
(
√
a
x
+
b
2
x
2
+
√
a
x
)
lim
x
⟶
0
+
b
2
b
√
a
(
√
a
+
b
2
x
+
√
a
)
b
√
a
⋅
2
√
a
⇒
b
2
a
=
3
⇒
b
a
=
6
© examsnet.com
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