For non zero solution of the system of linear equations; |
1
k
3
3
k
−2
2
4
−3
|=0 ⇒k=11 Now equations become x+11y+3z=0 ......(1) 3x+11y−2z=0 ......(2) 2x+4y−3z=0 ......(3) Adding equations (1) & (3) we get 3x+15y=0 ⇒x=−5y Now put x=−5y in equation (1), we get −5y+11y+3z=0 ⇒z=−2y ∴