] b(a+d)=0,b=0 or a=−d .....(1) c(a+d)=0,c=0 or a=−d .......(2) a2+bc=1,bc+d2=1 ........(3) ‘a’ and ‘d’ are diagonal elements a + d = 0 statement-1 is correct. Now, det(A)=ad−bc (3) a2+bc=1 and d2+bc=1 Now, from So, a2−d2=0 Adding a2+d2+2bc=2 ⇒(a+d)2−2ad+2bc=2 or 0−2(ad−bc)=2 So, ad−bc=1⇒det(A)=−1 So, statement -2 is also true. But statement -2 is not the correct explanation of statement- 1