For reflexive A=P−1AP is true For P=I, which is an invertible matrix. (A,A)∈R ∴R is reflexive. For symmetry As (A,B)∈R for matrix P A=P−1BP ⇒PAP−1=B ⇒B=PAP−1 ⇒B=(P−1)−1A(P−1) ∴(B,A)∈R for matrix P−1 ∴R is symmetric. For transitivity A=P−1BP and B=P−1CP ⇒A=P−1(P−1CP)P ⇒A=(P−1)2CP2 ⇒A=(P2)−1C(P2) ∴(A,C)∈R for matrix P2 ∴R is transitive. So R is equivalence. So, statement- 1 is true. We know that if A and B are two invertible matrices of order n, then (AB)−1=B−1A−1 So, statement- 2 is true.