|A|=ad−bc=15 where a,b,c,d∈{±3,±2,±1,0} Case I ad =9&bc=−6 For ad possible pairs are (3,3),(−3,−3) For bc possible pairs are (3,−2),(−3,2),(−2,3),(2,−3) So total matrix =2×4=8 Case II ad=6&bc=−9 Similarly total matrix =2×4=8 ⇒ Total such matrices are =16