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JEE Main Math Class 12 Integrals Part 1 Questions
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© examsnet.com
Question : 5
Total: 100
∫
2
x
+
5
√
7
−
6
x
−
x
2
d
x
=
A
√
7
−
6
x
−
x
2
+
B
sin
−
1
(
x
+
3
4
)
+
C
(where
C
is a constant of integration), then the ordered pair
(
A
,
B
)
is equal to
[Online April 15, 2018]
(-2,-1)
(2,-1)
(-2,1)
(2,1)
Validate
Solution:
∵
7
−
6
x
−
x
2
=
16
−
(
x
+
3
)
2
and
d
d
x
(
7
−
6
x
−
x
2
)
=
−
2
x
−
6
So,
∫
2
x
+
5
√
7
−
6
x
−
x
2
d
x
=
∫
2
x
+
6
√
7
−
6
x
−
x
2
d
x
−
∫
1
√
16
−
(
x
+
3
)
2
d
x
=
−
2
√
7
−
6
x
−
x
2
−
sin
−
1
(
x
+
3
4
)
+
C
Therefore,
A
=
−
2
,
&
B
=
−
1
© examsnet.com
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