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JEE Main Math Class 12 Inverse Trigonometric Functions Questions
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© examsnet.com
Question : 11
Total: 74
tan
−
1
(
1
+
√
3
3
+
√
3
)
+
s
e
c
−
1
(
√
8
+
4
√
3
6
+
3
√
3
)
is equal to
[24-Jan-2023 Shift 1]
π
4
π
2
π
3
π
6
Validate
Solution:
tan
−
1
(
1
+
√
3
3
+
√
3
)
+
s
e
c
−
1
(
√
8
+
4
√
3
6
+
3
√
3
)
=
tan
−
1
(
1
√
3
)
+
s
e
c
−
1
(
2
√
3
)
=
π
3
© examsnet.com
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