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JEE Main Math Class 12 Inverse Trigonometric Functions Questions
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© examsnet.com
Question : 27
Total: 74
sin
−
1
(
sin
2
π
3
)
+
cos
−
1
(
cos
7
π
6
)
+
tan
−
1
(
tan
3
π
4
)
is equal to:
[27-Jun-2022-Shift-1]
11
π
12
17
π
12
31
π
12
−
3
π
4
Validate
Solution:
sin
−
1
(
sin
2
π
3
)
+
cos
−
1
(
cos
7
π
6
)
+
tan
−
1
tan
(
3
π
4
)
sin
−
1
sin
(
2
π
3
)
=
π
−
2
π
3
=
π
3
cos
−
1
(
cos
2
π
6
)
=
2
π
−
7
π
6
=
5
π
6
tan
−
1
tan
(
3
π
4
)
=
3
π
4
−
π
=
−
π
4
sin
−
1
(
sin
2
π
3
)
+
cos
−
1
cos
7
π
6
+
tan
−
1
tan
3
π
4
=
11
π
12
© examsnet.com
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