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JEE Main Math Class 12 Limits and Derivatives Part 1 Questions
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© examsnet.com
Question : 4
Total: 100
lim
x
→
π
4
8
√
2
−
(
cos
x
+
sin
x
)
7
√
2
−
√
2
sin
2
x
is equal to
[25-Jul-2022-Shift-2]
14
7
14
√
2
7
√
2
Validate
Solution:
lim
x
→
π
4
8
√
2
−
(
cos
x
+
sin
x
)
7
√
2
−
√
2
sin
2
x
(
0
0
.
form
)
=
lim
x
→
π
4
−
7
(
cos
x
+
sin
x
)
6
(
−
sin
x
+
cos
x
)
−
2
√
2
cos
2
x
using L
−
H Rule
=
lim
x
→
π
4
56
(
cos
x
−
sin
x
)
2
√
2
cos
2
x
(
0
0
)
=
lim
x
→
π
4
−
56
(
sin
x
+
cos
x
)
−
4
√
2
sin
2
x
using L - H Rule
=
7
√
2
⋅
√
2
=
14
© examsnet.com
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