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Test Index
JEE Main Math Class 12 Limits and Derivatives Part 2 Questions
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© examsnet.com
Question : 35
Total: 56
lim
n
→
∞
{
(
2
1
2
−
2
1
3
)
(
2
1
2
−
2
1
5
)
.
.
.
.
.
.
(
2
1
2
−
2
1
2
n
+
1
)
}
is equal to
[6-Apr-2023 shift 2]
1
√
2
√
2
1
0
Validate
Solution:
P
=
lim
n
→
∞
(
2
1
2
−
2
1
3
)
(
2
1
2
−
2
1
5
)
.
.
.
.
.
.
.
.
(
2
1
2
−
2
1
2
n
+
1
)
Let
2
1
2
−
2
1
3
→
Smallest
2
1
2
−
2
1
2
n
+
1
→
Largest
Sandwich th.
(
2
1
2
−
2
1
3
)
n
≤
P
≤
(
2
1
2
−
2
1
2
2
n
+
1
)
n
(
lie
b
∕
w
0
and
1
)
n
lim
n
→
∞
(
2
1
2
−
2
1
3
)
n
=
0
lim
n
→
∞
(
2
1
2
−
2
1
2
n
+
1
)
n
=
0
∴
P
=
0
© examsnet.com
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