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JEE Main Math Class 12 Limits and Derivatives Part 2 Questions
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© examsnet.com
Question : 41
Total: 56
Let
f
(
x
)
=
s
i
n
x
+
cos
x
−
√
2
s
i
n
x
−
cos
x
,
x
∈
[
0
.
π
]
−
{
π
4
}
. Then
f
(
7
π
12
)
f
′
′
(
7
π
12
)
is equal to
[8-Apr-2023 shift 1]
−
2
3
2
9
−
1
3
√
3
2
3
√
3
Validate
Solution:
f
(
x
)
=
−
tan
(
x
2
−
π
8
)
f
′
(
x
)
=
−
1
2
s
e
c
2
(
x
2
−
π
8
)
f
′
′
(
x
)
=
−
s
e
c
2
(
x
2
−
π
8
)
⋅
tan
(
x
2
−
π
8
)
⋅
1
2
f
(
7
π
12
)
=
−
tan
(
π
6
)
=
−
1
√
3
f
′
′
(
7
π
12
)
=
−
1
2
s
e
c
2
π
6
⋅
tan
π
6
=
−
1
2
⋅
4
3
×
1
√
3
=
−
2
3
√
3
f
(
7
π
12
)
⋅
f
′
′
(
7
π
12
)
=
2
9
© examsnet.com
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