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JEE Main Math Class 12 Probability Part 1 Questions
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© examsnet.com
Question : 38
Total: 100
An urn contains 5 red and 2 green balls. Aball is drawn at random from the urn. If the drawn ball is green, then a red ball is added to the urn and if the drawn ball is red, then a green ball is added to the urn; the original ball is not returned to the urn. Now, a second ball is drawn at random from it. The probability that the second ball is red is:
[Jan. 09, 2019 (II)]
21
49
27
49
26
49
32
49
Validate
Solution:
Let G represents drawing a green ball and R represents drawing a red ball
So, the probability that second drawn ball is red
=
P
(
G
)
.
P
(
R
G
)
+
P
(
R
)
P
(
R
R
)
=
2
7
×
6
7
+
5
7
×
4
7
=
12
+
20
49
=
32
49
© examsnet.com
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