Let X and Y be two events such that P(X∪Y)=P(X∩Y) ......(1) We know P(X∪Y)=P(X)+P(Y)−P(X∩Y) P(X∩Y)=P(X)+P(Y)−P(X∩Y)( from (1) ⇒P(X)+P(Y)=2P(X∩Y) Hence, Statement -2 is true. Now, P(X∩Y′)=P(X)−P(X∩Y) and P(X′∩Y)=P(Y)−P(X∩Y) This implies statement- 1 is also true.