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JEE Main Math Class 12 Probability Part 2 Questions
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© examsnet.com
Question : 14
Total: 95
A fair die is tossed repeatedly until a six is obtained. Let
X
denote the number of tosses required and let
a
=
P
(
X
=
3
)
,
b
=
P
(
X
≥
3
)
and
c
=
P
(
X
≥
6
∣
X
>
3
)
. Then
b
+
c
a
is equal to___
[27-Jan-2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
a
=
P
(
X
=
3
)
=
5
6
×
5
6
×
1
6
=
25
216
b
=
P
(
X
≥
3
)
=
5
6
×
5
6
×
1
6
+
(
5
6
)
3
⋅
1
6
+
(
5
6
)
4
⋅
1
6
+
.
.
.
.
.
.
=
25
216
1
−
5
6
=
25
216
×
6
1
=
25
36
P
(
X
≥
6
)
=
(
5
6
)
5
⋅
1
6
+
(
5
6
)
6
⋅
1
6
+
.
.
.
.
.
.
.
.
=
(
5
6
)
5
⋅
1
6
1
−
5
6
=
(
5
6
)
5
c
=
(
5
6
)
5
(
5
6
)
3
=
25
36
b
+
c
a
=
(
5
6
)
2
+
(
5
6
)
2
(
5
6
)
2
⋅
1
6
=
12
© examsnet.com
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