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JEE Main Math Class 12 Probability Part 2 Questions
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© examsnet.com
Question : 43
Total: 95
25
%
of the population are smokers. A smoker has 27 times more chances to develop lung cancer then a non-smoker. A person is diagnosed with lung cancer and the probability that this person is a smoker is
k
10
. Then the value of
k
is ________.
[25-Jan-2023 Shift 2]
Your Answer:
Validate
Solution:
E
1
:
Smokers
P
(
E
1
)
=
1
4
E
2
:
non-smokers
P
(
E
2
)
=
3
4
E
: diagnosed with lung cancer
P
(
E
∕
E
1
)
=
27
28
P
(
E
∕
E
2
)
=
1
28
P
(
E
1
∕
E
)
=
P
(
E
1
)
P
(
E
∕
E
1
)
P
(
E
)
=
1
4
×
27
28
1
4
×
27
28
+
3
4
×
1
28
=
27
9
30
10
=
9
10
K
=
9
© examsnet.com
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