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JEE Main Math Class 12 Probability Part 2 Questions
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© examsnet.com
Question : 68
Total: 95
A biased die is marked with numbers
2
,
4
,
8
,
16
,
32
,
32
on its faces and the probability of getting a face with mark
n
is
1
n
. If the die is thrown thrice, then the probability, that the sum of the numbers obtained is 48 , is :
[25-Jun-2022-Shift-2]
7
2
11
7
2
12
3
2
10
13
2
12
Validate
Solution:
There are only two ways to get sum 48 , which are
(
32
,
8
,
8
)
and
(
16
,
16
,
16
)
So, required probability
=
3
(
2
32
⋅
1
8
⋅
1
8
)
+
(
1
16
⋅
1
16
⋅
1
16
)
=
3
2
10
+
1
2
12
=
13
2
12
© examsnet.com
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