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JEE Main Math Class 12 Three Dimensional Geometry Part 2 Questions
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© examsnet.com
Question : 33
Total: 100
Suppose the line
x
−
2
α
+
y
−
2
−
5
=
z
+
2
2
lies on the plane
x
+
3
y
−
2
z
+
β
=
0
. Then,
(
α
+
β
)
is equal to
[31 Aug 2021 Shift 2]
Your Answer:
Validate
Solution:
Given equation of line
x
−
2
α
=
y
−
2
−
5
=
z
+
2
2
...(i)
and plane
x
+
3
y
−
2
z
+
β
=
0
...(ii)
Line (i) pases through
(
2
,
2
,
−
2
)
which lies on plane (ii).
∴
2
+
6
+
4
+
β
=
0
⇒ β = −12
Also, given line is perpendicular to normal of the plane
α
(
1
)
−
5
(
3
)
+
2
(
−
2
)
=
0
⇒ α = 19
∴
α
+
β
=
7
© examsnet.com
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