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JEE Main Math Class 12 Three Dimensional Geometry Part 2 Questions
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© examsnet.com
Question : 94
Total: 100
If the line,
x
−
1
2
=
y
+
1
3
=
z
−
2
4
meets the plane,
x
+
2
y
+
3
z
=
15
at a point
P
,
then the distance of
P
from the origin is:
[April 09 2019 I]
√
5
∕
2
2
√
5
9
∕
2
7
∕
2
Validate
Solution:
Let point on line be
P
(
2
k
+
1
,
3
k
−
1
,
4
k
+
2
)
Since, point
P
lies on the plane
x
+
2
y
+
3
z
=
15
∴
2
k
+
1
+
6
k
−
2
+
12
k
+
6
=
15
⇒
k
=
1
2
∴
P
≡
(
2
,
1
2
,
4
)
Then the distance of the point
P
from the origin is
O
P
=
√
4
+
1
4
+
16
=
9
2
© examsnet.com
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