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JEE Main Math Class 12 Three Dimensional Geometry Part 2 Questions
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© examsnet.com
Question : 97
Total: 100
The equation of a plane containing the line of intersection of the planes
2
x
−
y
−
4
=
0
and
y
+
2
z
−
4
=
0
and passing through the point (1,1,0) is:
[April 08 2019 I]
x
−
3
y
−
2
z
=
−
2
2
x
−
z
=
2
x
−
y
−
z
=
0
x
+
3
y
+
z
=
4
Validate
Solution:
Let the equation of required plane be;
(
2
x
−
y
−
4
)
+
λ
(
y
+
2
z
−
4
)
=
0
∵
This plane passes through the point (1,1,0) then (2
−
1
−
4
)
+
λ
(
1
+
0
−
4
)
=
0
⇒
λ
=
−
1
Then, equation of required plane is,
(
2
x
−
y
−
4
)
−
(
y
+
2
z
−
4
)
=
0
⇒
2
x
−
2
y
−
2
z
=
0
⇒
x
−
y
−
z
=
0
© examsnet.com
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