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JEE Main Math Class 12 Three Dimensional Geometry Part 3 Questions
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© examsnet.com
Question : 52
Total: 134
If the eqation of the plane containing the line
x
+
2
y
+
3
z
−
4
=
02
x
+
y
−
z
+
5
and perpendicular to the plane
→
r
=
(
^
i
−
^
j
)
+
λ
(
^
i
+
^
j
+
^
k
)
+
µ
(
^
i
−
2
^
j
+
3
^
k
)
is ax+by
+
cz
=
4
, then
(
a
−
b
+
c
)
is equal to
[8-Apr-2023 shift 1]
22
24
20
18
Validate
Solution:
D.R's of line
→
n
1
=
−
5
^
i
+
7
^
j
−
3
^
k
D.R's of normal of second plane
→
n
2
=
5
^
i
−
2
^
j
−
3
^
k
→
n
1
×
→
n
2
=
−
27
^
i
−
30
^
j
−
25
^
k
A point on the required plane is
(
0
,
−
11
5
,
14
5
)
The equation of required plane is
27
x
+
30
y
+
25
z
=
4
∴
a
−
b
+
c
=
22
© examsnet.com
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