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JEE Main Math Class 12 Vector Algebra Part 1 Questions
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© examsnet.com
Question : 52
Total: 100
A body weighing 13 kg is suspended by two strings 5m and 12m long, their other ends being fastened to the extremities of a rod 13m long. If the rod be so held that the body hangs immediately below the middle point, then tensions in the strings are
[2007]
5 kg and 12 kg
5 kg and 13 kg
12 kg and 13 kg
5 kg and 5 k
Validate
Solution:
In
Δ
A
B
C
∵
13
2
=
5
2
+
12
2
⇒
A
B
2
=
A
C
2
+
B
C
2
⇒
∠
A
C
B
=
90
°
M
is mid point of the hypotenuse
A
B
,
therefore
M
A
=
M
B
=
M
C
⇒
∠
A
=
∠
A
C
M
=
θ
Applying Lami's theorem at
C
,
we get
T
1
sin
(
180
−
θ
)
=
T
2
sin
(
90
+
θ
)
=
13
k
g
sin
90
°
⇒
T
1
=
13
sin
θ
and
T
2
=
13
cos
θ
⇒
T
1
=
13
×
5
13
and
T
2
=
13
×
12
13
⇒
T
1
=
5
k
g
and
T
2
=
12
k
g
© examsnet.com
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