Test Index

Probability Part 1

Section: Mathematics

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Question : 13 of 100

Marks: +1, -0

Two dices are rolled. If both dices have six faces numbered 1, 2, 3, 5, 7 and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is

[17 Mar 2021 Shift 1]

$\frac{4}{9}$
$\frac{17}{36}$
$\frac{5}{12}$
$\frac{1}{2}$

Solution:

Six faces have numbers

\{1,2,3,5,7,11\}

.

Sum of the numbers on top faces of both the sides is less than or equal to 8

Then possible outcomes

(1,1),(1,2),(1,3),(1,5),(1,7)\rightarrow5

(2,1),(2,2),(2,3),(2,5)\rightarrow4

(3,1),(3,2),(3,3),(3,5)\rightarrow4

(5,1),(5,2),(5,3)\rightarrow3

(7,1)\rightarrow1

n(S)=5+4+4+3+1=17

Total number of outcomes

n(T)=6 \times 6=36

\therefore \;\;

Probability

=\frac{17}{36}

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