Given that, for x1,x2,...xn,A.M=x and variance =σ2 Now A.M of 2x1,2x2.....2xn=‌
2(x1+x2+...xn)
n
=2x But given A⋅M=4x ∴ Statement II is false. Variance of 2x1,2x2.....2xn = Variance of {2xi} =22 Variance of {xi}=4σ2 So, statement I is correct.