Equation of plane (x + y + z - 1) + λ (2x + 3y - z + 4) = 0 ⇒ (1 + 2λ) x + (1 + 3λ) y + (1 - λ) z - 1 + 4λ = 0 dr's of normal of the plane are 1 + 2λ , 1 + 3λ , 1 - λ Since plane is parallel to y - axis , 1 + 3λ = 0 ⇒ λ = - 1/3 So the equation of plane is x + 4z - 7 = 0 Point (3, 2, 1) satisfies this equation Hence Answer is (3)