Without loss of generalityLet ∣a1∣≤∣a2∣≤∣a3∣∣a∣2=∣a1∣2+∣a2∣2+∣a3∣2≥(a3)2⇒∣a∣≥∣a3∣=max{∣a1∣,∣a2∣,∣a3∣}A is true∣a∣2=∣a1∣2+∣a2∣2+∣a3∣2≤∣a3∣2+∣a3∣2+∣a3∣2⇒∣a∣2≤3∣a3∣2⇒∣a∣≤3∣a3∣=3max{∣a1∣,∣a2∣,∣a3∣}≤3max{∣a1∣,∣a2∣,∣a3∣}(2) is true