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JEE Main Physics Class 11 Gravitation Part 1 Questions
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© examsnet.com
Question : 18
Total: 100
The initial velocity
v
i
required to project a body vertically upward from the surface of the Earth to reach a height of
10
R
, where
R
is the radius of the Earth, may be described in terms of escape velocity
v
e
such that
v
i
=
√
x
y
×
v
e
.
The value of
x
will be ........... .
[25 Feb 2021 Shift 2]
Your Answer:
Validate
Solution:
By using law of conservation of energy,
Energy on the surface of earth
(
E
surface
)
=
Energy at height
(
h
=
10
R
)
⇒
−
G
M
m
R
+
1
2
m
v
i
2
=
−
G
M
m
R
+
10
R
+
0
=
−
G
M
m
11
R
⇒
1
∕
2
m
v
i
2
=
11
11
G
M
m
R
−
G
M
m
11
R
⇒
1
2
m
v
i
2
=
10
G
M
m
11
R
⇒
v
i
2
=
20
G
M
11
R
v
i
=
√
10
11
v
e
(
∵
v
e
=
√
2
G
M
R
=
escape velocity)
⇒
x
=
10
© examsnet.com
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