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JEE Main Physics Class 11 Gravitation Part 1 Questions
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© examsnet.com
Question : 61
Total: 100
A body of mass
m
is moving in a circular orbit of radius
R
about a planet of mass
M
. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius
R
2
,
and the other mass, in a circular orbit of radius
3
R
2
.
The difference between the final and initial total energies is:
[Online April 15, 2018]
−
G
M
m
2
R
+
G
M
m
6
R
−
G
M
m
6
R
G
M
m
2
R
Validate
Solution:
Initial gravitational potential energy,
E
i
=
−
G
M
m
2
R
Final gravitational potential energy,
E
f
=
−
G
M
m
∕
2
2
(
R
2
)
−
G
M
m
∕
2
2
(
3
R
2
)
=
−
G
M
m
2
R
−
G
M
m
6
R
=
−
4
G
M
m
6
R
=
−
2
G
M
m
3
R
therefore
Difference between initial and final energy,
E
f
−
E
i
=
G
M
m
R
(
−
2
3
+
1
2
)
=
−
G
M
m
6
R
© examsnet.com
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