Given, mass of man(m)=60kg Downward acceleration of lift, a=1.8ms−2 Let T be the tension in the rope connected with lift, g be the acceleration due to gravity (10ms−2). As, lift is moving in downward direction
∴mg−T=ma ⇒T=mg−ma=m(g−a) =60(10−1.8)=60×8.2 =492N Hence, the weight of the man during downward acceleration is 492N.