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JEE Main Physics Class 11 Kinetic Theory of Gases Part 1 Questions
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Question : 21
Total: 100
Consider a sample of oxygen behaving like an ideal gas. At
300
K
, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be (Molecular weight of oxygen is
32
g
/
m
o
l
;
R
=
8.3
J
K
−
1
m
o
l
−
1
)
[18 Mar 2021 Shift 2]
√
3
3
√
8
3
√
3
π
8
√
8
π
3
Validate
Solution:
The expression of the root mean square velocity of the gas molecules,
V
m
s
=
√
3
R
T
M
The expression of the average velocity of the gas molecules,
v
a
w
=
√
8
R
T
π
M
v
r
m
s
v
a
v
=
√
3
R
T
M
√
8
R
T
π
M
=
√
3
π
8
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