Given, the number of diatomic moles, n = 3 mol
The increase in temperature of the diatomic mole,
ΔT = 40ºC
Now, the degree of freedom,
f = linear + rotational + no oscillation
f = 3 + 2 + 0
f = 5
Change in internal energy,
ΔU=nCVΔT where,
CV=R=R Substituting the value in Eq. (i), we get
ΔU=nΔT Now, work done by the gas for isobaric process,
W=pΔV=nRΔT The ratio of the change in internal energy to the work done by thegas,
= = Multiply and divide the above equation with 5, we get
== Comparing with given equation,
= The value of the x = 25.