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JEE Main Physics Class 11 Kinetic Theory of Gases Part 1 Questions
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© examsnet.com
Question : 75
Total: 100
The temperature of an open room of volume
30
m
3
increases from
17
°
C
to
27
°
C
due to sunshine. The atmospheric pressure in the room remains
1
×
10
5
P
a
. If
n
i
and
n
f
are the number of molecules in the room before and after heating, then
n
f
−
n
i
will be :
[2017]
2.5
×
10
25
−
2.5
×
10
25
−
1.61
×
10
23
1.38
×
10
23
Validate
Solution:
Given: Temperature
T
i
=
17
+
273
=
290
K
Temperature
T
f
=
27
+
273
=
300
K
Atmospheric pressure,
P
0
=
1
×
10
5
P
a
Volume of room,
V
0
=
30
m
3
Difference in number of molecules,
n
f
−
n
i
=
?
Using ideal gas equation,
P
V
=
n
R
T
(
N
0
)
,
N
0
=
Avogadro's number
⇒
n
=
P
V
R
T
(
N
0
)
∴
n
f
−
n
i
=
P
0
V
0
R
(
1
T
f
−
1
T
i
)
N
0
=
1
×
10
5
×
30
8.314
×
6.023
×
10
23
(
1
300
−
1
290
)
=
−
2.5
×
10
25
© examsnet.com
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