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JEE Main Physics Class 11 Motion in a Straight Line and Plane Part 1 Questions
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© examsnet.com
Question : 72
Total: 100
A ball projected from ground at an angle of 45° just clears a wall in front. If point of projection is 4 m from the foot of wall and ball strikes the ground at a distance of 6 m on the other side of the wall, the height of the wall is :
[Online April 22, 2013]
4.4 m
2.4 m
3.6 m
1.6 m
Validate
Solution:
As ball is projected at an angle
45
°
to the horizontal therefore Range
=
4
H
or
10
=
4
H
⇒
H
=
10
4
=
2.5
m
(
∵
Range
=
4
m
+
6
m
=
10
m
)
Maximum height,
H
=
u
2
sin
2
θ
2
g
∴
u
2
=
H
×
2
g
sin
2
θ
=
2.5
×
2
×
10
(
1
√
2
)
2
=
100
or,
u
=
√
100
=
10
m
s
−
1
Height of wall PA
=
OA
tan
θ
−
1
2
g
(
O
A
)
2
u
2
cos
2
θ
=
4
−
1
2
×
10
×
16
10
×
10
×
1
√
2
×
1
√
2
=
2.4
m
© examsnet.com
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