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JEE Main Physics Class 11 Motion in a Straight Line and Plane Part 1 Questions
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© examsnet.com
Question : 8
Total: 100
Two spherical balls having equal masses with radius of
5
cm
each are thrown upwards along the same vertical direction at an interval of
3
s
with the same initial velocity of
35
m
∕
s
, then these balls collide at a height
of ..........m. (Take,
g
=
10
m
∕
s
2
)
[26 Aug 2021 Shift 1]
Your Answer:
Validate
Solution:
Given,
m
1
=
m
2
=
m
r
1
=
r
2
=
r
=
5
cm
=
5
×
10
−
2
m
u
1
=
u
2
=
35
m
∕
s
t
1
=
0
and
t
2
=
3
s
When both ball will collide,
(
S
1
)
vertical
=
(
S
2
)
vertical
Let after time t both ball will collide.
(
S
1
)
vertical
=
u
1
t
−
1
2
g
t
2
(
S
2
)
vertical
=
u
2
(
t
−
3
)
−
1
2
g
(
t
−
3
)
2
From Eq. (i), we have
⇒
u
1
t
−
1
2
g
t
2
=
u
2
(
t
−
3
)
−
1
2
g
(
t
−
3
)
2
⇒
35
t
−
1
2
×
10
×
t
2
=
35
(
t
−
3
)
−
1
2
×
10
(
t
−
3
)
2
⇒
35
t
−
35
(
t
−
3
)
=
5
t
2
−
5
(
t
−
3
)
2
⇒
35
(
t
−
t
+
3
)
=
5
[
t
2
−
(
t
−
3
)
2
]
35
×
3
=
5
(
t
+
t
−
3
)
(
t
−
t
+
3
)
⇒
105
5
=
(
2
t
−
3
)
(
3
)
⇒
21
3
=
2
t
−
3
⇒
7
=
2
t
−
3
⇒
2
t
=
10
⇒
t
=
5
s
So, the height at which ball will collide is
(
S
1
)
vertical
=
u
1
t
−
1
2
g
t
2
=
35
×
5
−
1
2
×
10
×
(
5
)
2
=
175
−
125
=
50
m
© examsnet.com
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