Given, horizontal velocity of helicopter,
ux=v Height of the helicopter from ground = h
The given condition can be drawn in the figure given below
Here, M is the position of man.
Let, time taken by food packet to reach ground from helicopter = t
Acceleration due to gravity,
g=10ms−2 Initial velocity of food packet along Y-axis,
uy=0 Since,
h=uyt+gt2 ∴t=√ and distance travelled by helicopter in time t along horizontal direction
⇒x=uxt =v√ Hence, distance of helicopter from man,
H=√h2+x2=√h2+(v√)2 =√h2+