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JEE Main Physics Class 11 Oscillations Part 1 Questions
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© examsnet.com
Question : 17
Total: 100
The displacement time graph of a particle executing S.H.M. is given in figure : (sketch is schematic and not to scale)
Which of the following statements is/are true for this motion?
(1) The force is zero at
t
=
3
T
4
(2) The acceleration is maximum at
t
=
T
(3) The speed is maximum at
t
=
T
4
(4) The P.E. is equal to K.E. of the oscillation at
t
=
T
2
[Sep. 02, 2020 (II)]
(1),(2) and (4)
(2),(3) and (4)
(1),(2) and (3)
(1) and (4)
Validate
Solution:
From graph equation of SHM
X
=
A
cos
ω
t
(1) At
3
T
4
particle is at mean position.
∴
Acceleration
=
0
,
Force
=
0
(2) At
T
particle again at extreme position so acceleration ismaximum.
(3) At
t
=
T
4
,
particle is at mean position so velocity is maximum.
Acceleration
=
0
(4) When
K
E
=
P
E
⇒
1
2
k
(
A
2
−
x
2
)
=
1
2
k
x
2
Here,
A
=
amplitude of SHM
x
=
displacement from mean position
⇒
A
2
=
2
x
2
⇒
x
=
+
A
√
2
⇒
A
√
2
=
A
cos
ω
t
⇒
t
=
T
2
∴
x
=
−
A
which is not possible
∴
1
,
2
and 3 are correct.
© examsnet.com
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